Solvedsnowboy Call start() again after terminate()
kgorszczyk posts at
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Original✔️Accepted Answer
Yes that should be easy, just move the last two lines in HotwordDetector.__init__()
of snowboydecoder.py
:
self.audio = pyaudio.PyAudio()
self.stream_in = self.audio.open(
input=True, output=False,
format=self.audio.get_format_from_width(
self.detector.BitsPerSample() / 8),
channels=self.detector.NumChannels(),
rate=self.detector.SampleRate(),
frames_per_buffer=2048,
stream_callback=audio_callback)
down to the start of the start()
function, then you can repeatedly call terminate()
and start()
!
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snowboy Call start() again after terminate()
Yes that should be easy just move the last two lines in HotwordDetector.__init__() of snowboydecoder...
Hi,
im trying to add snowboy to a personal assistant app i've been working on but to be able to record the audio i first need to terminate all recording streams from snowboy otherwise i get an Audio Deivce Busy Error.
After accessing detector.terminate() I can finally record my command and the python file processes it correctly. My only problem is, that while the prog loops detector.start(...) does not work anymore.
Is there a way to reenable detector.start(...) so snowboy listens for the Hotword and then kill everything with detector.terminate() (And so on and on)?
Thanks :)